x^2-3x=16x+60

Solution for x^2-3x=16x+60 equation:

x^2-3x=16x+60

We move all terms to the left:

x^2-3x-(16x+60)=0

We get rid of parentheses

x^2-3x-16x-60=0

We add all the numbers together, and all the variables

x^2-19x-60=0

a = 1; b = -19; c = -60;
Δ = b2-4ac
Δ = -192-4·1·(-60)
Δ = 601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{601}}{2*1}=\frac{19-\sqrt{601}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{601}}{2*1}=\frac{19+\sqrt{601}}{2}
$